A Brownian piece in front of a process absolutely continuous with respect to Brownian motion

Burdzy and Scheutzow asked whether, for every process $(X_t)_{t\ge0}$ whose law is equivalent to Wiener measure, one can put a random piece of path in front of $X$ so that the new process is a Brownian motion. We show that the answer is yes, and that absolute continuity suffices: on an extension of the probability space there are a Brownian motion $B$ and an almost surely finite random integer $N\ge0$ with $X_t=B_{N+t}-B_N$ for all $t\ge0$, so that $(B_t)_{0\le t\le N}$ is the required piece. The proof is Rost's filling scheme for the unit shift of two-sided Brownian motion. We give it in the form of a criterion for an invertible measure-preserving map $\theta$ and a target law $fP$: a randomized forward shift $\theta^N$ carries $P$ to $fP$ if and only if $\mathbb E[f\mid\mathcal I]=1$, where $\mathcal I$ is the invariant $\sigma$-field. The time $N$ cannot in general be a stopping time for $B$, and the auxiliary randomness cannot be dropped from the criterion.

Authors

Institutions

Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2026-11-08
DOI
https://doi.org/10.5281/zenodo.24069912
Primary Topic
Stochastic processes and statistical mechanics
Type
preprint
Controls
|||
ALL TIME
JAN
FEB
MAR
APR
MAY
JUN
JUL
AUG
SEP
OCT
NOV
preprint

A Brownian piece in front of a process absolutely continuous with respect to Brownian motion

Yitzchak Shmalo
Zenodo (CERN European Organization for Nuclear Research)
Stochastic processes and statistical mechanics
preprint

A Brownian piece in front of a process absolutely continuous with respect to Brownian motion

Yitzchak Shmalo
preprint en

Abstract

Burdzy and Scheutzow asked whether, for every process $(X_t)_{t\ge0}$ whose law is equivalent to Wiener measure, one can put a random piece of path in front of $X$ so that the new process is a Brownian motion. We show that the answer is yes, and that absolute continuity suffices: on an extension of the probability space there are a Brownian motion $B$ and an almost surely finite random integer $N\ge0$ with $X_t=B_{N+t}-B_N$ for all $t\ge0$, so that $(B_t)_{0\le t\le N}$ is the required piece. The proof is Rost's filling scheme for the unit shift of two-sided Brownian motion. We give it in the form of a criterion for an invertible measure-preserving map $\theta$ and a target law $fP$: a randomized forward shift $\theta^N$ carries $P$ to $fP$ if and only if $\mathbb E[f\mid\mathcal I]=1$, where $\mathcal I$ is the invariant $\sigma$-field. The time $N$ cannot in general be a stopping time for $B$, and the auxiliary randomness cannot be dropped from the criterion.

Zenodo (CERN European Organization for Nuclear Research)
Hebrew University of Jerusalem (IL)
Stochastic processes and statistical mechanics
AI Navigator

Ask Laika to Summarize, Analyze, and Connect papers live on the map.

Summarize Papers & Methodologies

Extract key findings, datasets, and comparative methods across publications.

Benchmark Rankings & Visual Analytics

Rank top research institutions, authors, funders, topics, and journals by Field-Weighted Citation Impact (FWCI) and paper volume with instant charts.

Connect Distant Disciplines

Bridge topological clusters on the map to find hidden collaborative intersections.

Laika access coming soon