The complete graph maximizes the variance of the antivoter model

In the antivoter model on a finite graph each vertex, at rate one, adopts the opinion opposite to that of a uniformly chosen neighbour. Let $S$ be the sum of the $\pm1$ opinions in stationarity. Aldous and Fill asked whether, among regular graphs on $n$ vertices, $\operatorname{Var} S$ is largest for the complete graph, where it equals $n(n-2)/(2n-3)$. We prove that it is: for every connected non-bipartite regular graph on $n\ge3$ vertices and every stationary distribution, $\operatorname{Var} S\le n(n-2)/(2n-3)$, with equality only for $K_n$. The proof writes the pair correlations as the solution of a Sylvester equation and reduces the question to a lower bound on the diagonal of $(I+P)^{-1}$, where $P$ is the transition matrix of simple random walk. For vertex-transitive graphs the same argument gives $\operatorname{Var} S=n^2/\bigl(2\sum_i(1+\lambda_i)^{-1}\bigr)$, the sum running over the eigenvalues of $P$.

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Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2026-11-08
DOI
https://doi.org/10.5281/zenodo.24064369
Primary Topic
Opinion Dynamics and Social Influence
Type
preprint
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preprint

The complete graph maximizes the variance of the antivoter model

Yitzchak Shmalo
Zenodo (CERN European Organization for Nuclear Research)
Opinion Dynamics and Social Influence
preprint

The complete graph maximizes the variance of the antivoter model

Yitzchak Shmalo
preprint en

Abstract

In the antivoter model on a finite graph each vertex, at rate one, adopts the opinion opposite to that of a uniformly chosen neighbour. Let $S$ be the sum of the $\pm1$ opinions in stationarity. Aldous and Fill asked whether, among regular graphs on $n$ vertices, $\operatorname{Var} S$ is largest for the complete graph, where it equals $n(n-2)/(2n-3)$. We prove that it is: for every connected non-bipartite regular graph on $n\ge3$ vertices and every stationary distribution, $\operatorname{Var} S\le n(n-2)/(2n-3)$, with equality only for $K_n$. The proof writes the pair correlations as the solution of a Sylvester equation and reduces the question to a lower bound on the diagonal of $(I+P)^{-1}$, where $P$ is the transition matrix of simple random walk. For vertex-transitive graphs the same argument gives $\operatorname{Var} S=n^2/\bigl(2\sum_i(1+\lambda_i)^{-1}\bigr)$, the sum running over the eigenvalues of $P$.

Zenodo (CERN European Organization for Nuclear Research)
Hebrew University of Jerusalem (IL)
Opinion Dynamics and Social Influence
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