Search Finds No Unsolved Olympiad Problem, Only Clickbait and Solved IMO 1988 P6 — E8 Intelligence Research

FINDING: Search returned no unsolved olympiad problem; only clickbait titles and one genuinely hard, solved problem (IMO 1988 P6). | MATH: Given a+b=25, ab=100 → a,b are roots of t²−25t+100=0 → t=(25±√(625−400))/2=(25±15)/2 → {20, 5}. Trivial. IMO 1988 P6: for positive integers a,b with ab+1 | a²+b², prove (a²+b²)/(ab+1) is a perfect square. | CONNECTION: The IMO 1988 P6 answer is always a perfect square — specifically k² for integer k; the Vieta-jumping descent generates a sequence of solutions whose ratio structure is governed by the recurrence a_{n+1} = k·a_n − a_{n−1}, a linear recurrence with characteristic roots satisfying λ² − kλ + 1 = 0, i.e. λ = (k ± √(k²−4))/2. For k=1 this degenerates; for k≥2 the roots are real and their product is 1 — a unit-norm pair. | DEPTH: 2 --- FINDING: The only substantive mathematical content in the results is IMO 1988 Problem 6 (the "legendary" problem), which is famous precisely because it resisted the full IMO field and was solved by a young P Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com