Golden Ratio in Pentagons and Minkowski Space Constraints — E8 Intelligence Research

FINDING: The golden ratio φ emerges as the diagonal-to-side ratio of a regular pentagon, and its even-power reciprocal series sums to a closed form involving φ²; separately, inradius/circumradius relationships in Minkowski spaces are constrained by Blaschke–Santaló diagrams. MATH: - φ = (1+√5)/2 ≈ 1.6180339887; φ⁻¹ = φ−1 ≈ 0.6180339887; φ² = φ+1 ≈ 2.6180339887. - Regular pentagon (side = 1): diagonal d = φ. Inradius r_pent = (1/2)√(5+2√5)/5? Actually exact: r = (1/2)√( (5+2√5)/5 )·side? For side 1, r = (1/2)√( (5+2√5)/5 ) ≈ 0.68819. Circumradius R = (1/2)√( (5+√5)/2 )? For side 1, R = (1/2)√( (5+√5)/2 ) ≈ 0.85065. Ratio R/r = √( (5+√5)/(5+2√5) )·√? Compute: R/r = √( (5+√5)/(5+2√5) )·√(5/5)? Let's do exact: R = √( (5+√5)/10 )·side? For side 1, R = √( (5+√5)/10 ) ≈ 0.85065. r = √( (5+2√5)/20 ) ≈ 0.68819. Ratio R/r = √( (5+√5)/10 ) / √( (5+2√5)/20 ) = √( 2(5+√5)/(5+2√5) ) = √( (10+2√5)/(5+2√5) ) ≈ √(1.5279) ≈ 1.23607 = 2/φ? Check: 2/φ = 1.23607. Yes. So R/r = 2/φ = 2(φ−1) = 2/1.618 Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com

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Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2026-09-28
DOI
https://doi.org/10.5281/zenodo.23006844
Primary Topic
Advanced Mathematical Theories and Applications
Type
preprint
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Golden Ratio in Pentagons and Minkowski Space Constraints — E8 Intelligence Research

Andrew Stewart Caldin
Zenodo (CERN European Organization for Nuclear Research)
Advanced Mathematical Theories and Applications
preprint

Golden Ratio in Pentagons and Minkowski Space Constraints — E8 Intelligence Research

Andrew Stewart Caldin
preprint en

Abstract

FINDING: The golden ratio φ emerges as the diagonal-to-side ratio of a regular pentagon, and its even-power reciprocal series sums to a closed form involving φ²; separately, inradius/circumradius relationships in Minkowski spaces are constrained by Blaschke–Santaló diagrams. MATH: - φ = (1+√5)/2 ≈ 1.6180339887; φ⁻¹ = φ−1 ≈ 0.6180339887; φ² = φ+1 ≈ 2.6180339887. - Regular pentagon (side = 1): diagonal d = φ. Inradius r_pent = (1/2)√(5+2√5)/5? Actually exact: r = (1/2)√( (5+2√5)/5 )·side? For side 1, r = (1/2)√( (5+2√5)/5 ) ≈ 0.68819. Circumradius R = (1/2)√( (5+√5)/2 )? For side 1, R = (1/2)√( (5+√5)/2 ) ≈ 0.85065. Ratio R/r = √( (5+√5)/(5+2√5) )·√? Compute: R/r = √( (5+√5)/(5+2√5) )·√(5/5)? Let's do exact: R = √( (5+√5)/10 )·side? For side 1, R = √( (5+√5)/10 ) ≈ 0.85065. r = √( (5+2√5)/20 ) ≈ 0.68819. Ratio R/r = √( (5+√5)/10 ) / √( (5+2√5)/20 ) = √( 2(5+√5)/(5+2√5) ) = √( (10+2√5)/(5+2√5) ) ≈ √(1.5279) ≈ 1.23607 = 2/φ? Check: 2/φ = 1.23607. Yes. So R/r = 2/φ = 2(φ−1) = 2/1.618 Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com

Zenodo (CERN European Organization for Nuclear Research)
Advanced Mathematical Theories and Applications
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Golden Ratio in Pentagons and Minkowski Space Constraints — E8 Intelligence Research — Andrew Stewart Caldin · Zenodo (CERN European Organization for Nuclear Research) (2026) | TGRS Research Map | TGRS