Iterated convolution inequalities on R d $\mathbb {R}^d$ double struck upper R Superscript d and Riemannian symmetric spaces of non-compact type

Abstract Let X $\\mathbb {X}$ double struck upper X be a Riemannian symmetric space of non-compact type. For a real-valued f ∈ L 1 ( X ) $f \\in L^1(\\mathbb {X})$ f element of upper L Superscript 1 Baseline left parenthesis double struck upper X right parenthesis with ∫ X f ≥ 0 $\\int _{\\mathbb {X}} f \\ge 0$ integral Underscript double struck upper X Endscripts f greater than or equals 0 , we prove that if f satisfies the iterated convolution inequality: f ≥ ∑ n = 2 N a n ( ∗ n f ) , a.e. on X , $$ \\begin{align*} f \\ge \\sum_{n=2}^N a_n \\left(*^n f\\right),\\:\\:\\text{ a.e. on } \\mathbb{X}, \\end{align*} $$ where N ≥ 2 $N \\ge 2$ upper N greater than or equals 2 is an integer and for 2 ≤ n ≤ N $2 \\le n \\le N$ 2 less than or equals n less than or equals upper N </

Authors

Institutions

Publication Details

Journal
Canadian Journal of Mathematics
Published
2026-09-21
DOI
https://doi.org/10.4153/s0008414x26102442
Primary Topic
Advanced Harmonic Analysis Research
Type
article
Field-Weighted Citation Impact
0.00
Controls
|||
ALL TIME
JAN
FEB
MAR
APR
MAY
JUN
JUL
AUG
SEP
article

Iterated convolution inequalities on R d $\mathbb {R}^d$ double struck upper R Superscript d and Riemannian symmetric spaces of non-compact type

Utsav Dewan
Canadian Journal of Mathematics
Advanced Harmonic Analysis Research
article

Iterated convolution inequalities on R d $\mathbb {R}^d$ double struck upper R Superscript d and Riemannian symmetric spaces of non-compact type

Utsav Dewan
article en

Abstract

Abstract Let X $\mathbb {X}$ double struck upper X be a Riemannian symmetric space of non-compact type. For a real-valued f ∈ L 1 ( X ) $f \in L^1(\mathbb {X})$ f element of upper L Superscript 1 Baseline left parenthesis double struck upper X right parenthesis with ∫ X f ≥ 0 $\int _{\mathbb {X}} f \ge 0$ integral Underscript double struck upper X Endscripts f greater than or equals 0 , we prove that if f satisfies the iterated convolution inequality: f ≥ ∑ n = 2 N a n ( ∗ n f ) , a.e. on X , $$ \begin{align*} f \ge \sum_{n=2}^N a_n \left(*^n f\right),\:\:\text{ a.e. on } \mathbb{X}, \end{align*} $$ where N ≥ 2 $N \ge 2$ upper N greater than or equals 2 is an integer and for 2 ≤ n ≤ N $2 \le n \le N$ 2 less than or equals n less than or equals upper N </

Canadian Journal of Mathematics
Indian Institute of Technology Bombay (IN)
Reduced inequalities
Openalex Percentile: Top 6%
Advanced Harmonic Analysis Research
AI Navigator

Ask Laika to Summarize, Analyze, and Connect papers live on the map.

Summarize Papers & Methodologies

Extract key findings, datasets, and comparative methods across publications.

Benchmark Rankings & Visual Analytics

Rank top research institutions, authors, funders, topics, and journals by Field-Weighted Citation Impact (FWCI) and paper volume with instant charts.

Connect Distant Disciplines

Bridge topological clusters on the map to find hidden collaborative intersections.