The Averaged Representation Count of an Additive Basis

For $A \\subseteq \\mathbb{N}$ let $r_A(n)$ count the ordered pairs from $A$ summing to $n$. The partial sum $\\sum_{n<N} r_A(n)$ is not an approximation to anything: it counts exactly the pairs from $A$ whose sum lies below $N$, and both entries of such a pair are themselves below $N$. Hence the partial sum is at most $|A \\cap [0,N)|^2$. If $A$ is a basis of order two then the same partial sum is at least $N - N_0$, because every large $n$ has a representation. The two bounds together give the square-root density estimate $N - N_0 \\le |A \\cap [0,N)|^2$, and they squeeze the average $N^{-1}\\sum_{n

Authors

Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2026-09-21
DOI
https://doi.org/10.5281/zenodo.22849332
Primary Topic
Limits and Structures in Graph Theory
Type
preprint
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preprint

The Averaged Representation Count of an Additive Basis

Christopher Mills
Zenodo (CERN European Organization for Nuclear Research)
Limits and Structures in Graph Theory
preprint

The Averaged Representation Count of an Additive Basis

Christopher Mills
preprint en

Abstract

For $A \subseteq \mathbb{N}$ let $r_A(n)$ count the ordered pairs from $A$ summing to $n$. The partial sum $\sum_{n<N} r_A(n)$ is not an approximation to anything: it counts exactly the pairs from $A$ whose sum lies below $N$, and both entries of such a pair are themselves below $N$. Hence the partial sum is at most $|A \cap [0,N)|^2$. If $A$ is a basis of order two then the same partial sum is at least $N - N_0$, because every large $n$ has a representation. The two bounds together give the square-root density estimate $N - N_0 \le |A \cap [0,N)|^2$, and they squeeze the average $N^{-1}\sum_{n

Zenodo (CERN European Organization for Nuclear Research)
Limits and Structures in Graph Theory
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The Averaged Representation Count of an Additive Basis — Christopher Mills · Zenodo (CERN European Organization for Nuclear Research) (2026) | TGRS Research Map | TGRS