Undecidability of the Spectral Gap via Halting Problem Reduction — E8 Intelligence Research

FINDING: The halting problem is provably undecidable; reductions show many other problems inherit this undecidability, including the spectral gap problem via Penrose tiling encoding. MATH: - Halting problem: No Turing machine \( H \) exists such that \( H(P, I) \) decides if program \( P \) halts on input \( I \). - Reduction: If problem \( A \) can be encoded as a halting problem instance, then \( A \) is undecidable. - Cubitt et al. (2015): The spectral gap problem (determining if a quantum system has a gap between ground and first excited state) is undecidable. Encoding uses aperiodic tilings (Penrose-like) to simulate a Turing machine's tape and state. - Key constants/ratios: None directly from these findings; the undecidability proof relies on combinatorial tiling rules, not numeric constants. CONNECTION: - Penrose tilings exhibit 5-fold rotational symmetry (crystallographically forbidden in periodic lattices) and use golden ratio \(\phi = (1+\sqrt{5})/2 \approx 1.618\ Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com

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Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2026-07-27
DOI
https://doi.org/10.5281/zenodo.21617240
Primary Topic
Quasicrystal Structures and Properties
Type
preprint
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Undecidability of the Spectral Gap via Halting Problem Reduction — E8 Intelligence Research

Andrew Stewart Caldin
Zenodo (CERN European Organization for Nuclear Research)
Quasicrystal Structures and Properties
preprint

Undecidability of the Spectral Gap via Halting Problem Reduction — E8 Intelligence Research

Andrew Stewart Caldin
preprint en

Abstract

FINDING: The halting problem is provably undecidable; reductions show many other problems inherit this undecidability, including the spectral gap problem via Penrose tiling encoding. MATH: - Halting problem: No Turing machine \( H \) exists such that \( H(P, I) \) decides if program \( P \) halts on input \( I \). - Reduction: If problem \( A \) can be encoded as a halting problem instance, then \( A \) is undecidable. - Cubitt et al. (2015): The spectral gap problem (determining if a quantum system has a gap between ground and first excited state) is undecidable. Encoding uses aperiodic tilings (Penrose-like) to simulate a Turing machine's tape and state. - Key constants/ratios: None directly from these findings; the undecidability proof relies on combinatorial tiling rules, not numeric constants. CONNECTION: - Penrose tilings exhibit 5-fold rotational symmetry (crystallographically forbidden in periodic lattices) and use golden ratio \(\phi = (1+\sqrt{5})/2 \approx 1.618\ Author: Andrew Stewart Caldin, Independent Researcher, UK. Part of the E8 Intelligence Research series. Platform: e8intelligence.com

Zenodo (CERN European Organization for Nuclear Research)
Quasicrystal Structures and Properties
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Undecidability of the Spectral Gap via Halting Problem Reduction — E8 Intelligence Research — Andrew Stewart Caldin · Zenodo (CERN European Organization for Nuclear Research) (2026) | TGRS Research Map | TGRS