Lu Collatz Reverse Pruning Sieve (2026): A Dichotomy Proof of the Collatz Conjecture

This paper presents a complete proof of the Collatz conjecture. We establish three foundational facts: (1) every even number reduces to an odd number; (2) every odd number belongs to exactly one of the three classes 6a + 1, 6a + 3, or 6a + 5; (3) numbers of the form 6a + 3 (odd multiples of 3) serve as the base case, since their forward orbits eventually reach 1. By constructing a “pruned reverse tree” sieve, we prove that any number in the classes 6a+1 or 6a+5, if it is a counterexample, must survive all ffnite levels of the sieve and therefore must belong to the 3-adic limit intersection R∞. We characterize R∞ algebraically as the set of numbers of the form k · 3 n − 1. Then, using the accelerated Collatz map T(n) = (3n +1)/2 v_2(3n+1) , we prove that any such number either strictly collapses to a smaller number, or escapes from R∞ within ffnitely many steps; in both cases, the argument reduces to induction. All rigorous derivations are provided in the full paper.

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Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2026-07-22
DOI
https://doi.org/10.5281/zenodo.21482853
Primary Topic
Benford’s Law and Fraud Detection
Type
article
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article

Lu Collatz Reverse Pruning Sieve (2026): A Dichotomy Proof of the Collatz Conjecture

Ping Lu
Zenodo (CERN European Organization for Nuclear Research)
Benford’s Law and Fraud Detection
article

Lu Collatz Reverse Pruning Sieve (2026): A Dichotomy Proof of the Collatz Conjecture

Ping Lu
article en

Abstract

This paper presents a complete proof of the Collatz conjecture. We establish three foundational facts: (1) every even number reduces to an odd number; (2) every odd number belongs to exactly one of the three classes 6a + 1, 6a + 3, or 6a + 5; (3) numbers of the form 6a + 3 (odd multiples of 3) serve as the base case, since their forward orbits eventually reach 1. By constructing a “pruned reverse tree” sieve, we prove that any number in the classes 6a+1 or 6a+5, if it is a counterexample, must survive all ffnite levels of the sieve and therefore must belong to the 3-adic limit intersection R∞. We characterize R∞ algebraically as the set of numbers of the form k · 3 n − 1. Then, using the accelerated Collatz map T(n) = (3n +1)/2 v_2(3n+1) , we prove that any such number either strictly collapses to a smaller number, or escapes from R∞ within ffnitely many steps; in both cases, the argument reduces to induction. All rigorous derivations are provided in the full paper.

Zenodo (CERN European Organization for Nuclear Research)
Openalex Percentile: Top 6%
Benford’s Law and Fraud Detection
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