Surface groups among cubulated hyperbolic and one-relator groups
Let $X$ be a non-positively curved cube complex with hyperbolic fundamental group. We prove that $\pi_1(X)$ has a non-free subgroup of infinite index unless $\pi_1(X)$ is either free or a surface group, answering questions of Gromov and Whyte (in a special case) and Wise. A similar result for one-relator groups follows, answering a question posed by several authors. The proof relies on a careful analysis of free and cyclic splittings of cubulated groups.
Authors
- Henry Wilton (ORCID: https://orcid.org/0000-0001-6369-9478)
Publication Details
- Journal
- Apollo (University of Cambridge)
- Published
- 2026-01-29
- DOI
- https://doi.org/10.17863/cam.125292
- Primary Topic
- Geometric and Algebraic Topology
- Type
- article
- Field-Weighted Citation Impact
- 0.00