Surface groups among cubulated hyperbolic and one-relator groups

Let $X$ be a non-positively curved cube complex with hyperbolic fundamental group. We prove that $\pi_1(X)$ has a non-free subgroup of infinite index unless $\pi_1(X)$ is either free or a surface group, answering questions of Gromov and Whyte (in a special case) and Wise. A similar result for one-relator groups follows, answering a question posed by several authors. The proof relies on a careful analysis of free and cyclic splittings of cubulated groups.

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Publication Details

Journal
Apollo (University of Cambridge)
Published
2026-01-29
DOI
https://doi.org/10.17863/cam.125292
Primary Topic
Geometric and Algebraic Topology
Type
article
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article

Surface groups among cubulated hyperbolic and one-relator groups

Henry Wilton
Apollo (University of Cambridge)
Geometric and Algebraic Topology
article

Surface groups among cubulated hyperbolic and one-relator groups

Henry Wilton
article en

Abstract

Let $X$ be a non-positively curved cube complex with hyperbolic fundamental group. We prove that $\pi_1(X)$ has a non-free subgroup of infinite index unless $\pi_1(X)$ is either free or a surface group, answering questions of Gromov and Whyte (in a special case) and Wise. A similar result for one-relator groups follows, answering a question posed by several authors. The proof relies on a careful analysis of free and cyclic splittings of cubulated groups.

Apollo (University of Cambridge)
Reduced inequalities
Openalex Percentile: Top 68%
Geometric and Algebraic Topology
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Surface groups among cubulated hyperbolic and one-relator groups — Henry Wilton · Apollo (University of Cambridge) (2026) | TGRS Research Map | TGRS