An injective martingale coupling

We give an injective martingale coupling; in particular, given measures μ and ν in convex order on R such that ν is continuous, we construct a martingale transport such that for each y in the support of the target law ν there is a unique x in a support of the initial law μ such that (some of) the mass at x is transported to y . Then π has disintegration π ( d x , d y ) = ν ( d y ) δ θ ( y ) ( d x ) for some function θ . More precisely we construct a martingale coupling π of the measures μ and ν such that there is a set Γ μ such that μ ( Γ μ ) = 1 and a disintegration ( π x ) x ∈ Γ μ of π of the form π ( d x , d y ) = π x ( d y ) μ ( d x ) such that, with Γ π x a support of π x , we have # { x ∈ Γ μ : y ∈ Γ π x } ∈ { 0 , 1 } for all y and { y : # { x ∈ Γ μ : y ∈ Γ π x } = 1 } = supp ( ν ) . Moreover, if μ is continuous we may take Γ π x = supp ( π x ) for each x . However, we cannot also insist that Γ μ = supp ( μ ) .

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Publication Details

Journal
Stochastic Processes and their Applications
Published
2026-01-12
DOI
https://doi.org/10.1016/j.spa.2026.104883
Primary Topic
Mathematical Dynamics and Fractals
Type
article
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article

An injective martingale coupling

Dominykas Norgilas, David Hobson
Stochastic Processes and their Applications
Mathematical Dynamics and Fractals
article

An injective martingale coupling

Dominykas Norgilas, David Hobson
article en

Abstract

We give an injective martingale coupling; in particular, given measures μ and ν in convex order on R such that ν is continuous, we construct a martingale transport such that for each y in the support of the target law ν there is a unique x in a support of the initial law μ such that (some of) the mass at x is transported to y . Then π has disintegration π ( d x , d y ) = ν ( d y ) δ θ ( y ) ( d x ) for some function θ . More precisely we construct a martingale coupling π of the measures μ and ν such that there is a set Γ μ such that μ ( Γ μ ) = 1 and a disintegration ( π x ) x ∈ Γ μ of π of the form π ( d x , d y ) = π x ( d y ) μ ( d x ) such that, with Γ π x a support of π x , we have # { x ∈ Γ μ : y ∈ Γ π x } ∈ { 0 , 1 } for all y and { y : # { x ∈ Γ μ : y ∈ Γ π x } = 1 } = supp ( ν ) . Moreover, if μ is continuous we may take Γ π x = supp ( π x ) for each x . However, we cannot also insist that Γ μ = supp ( μ ) .

Stochastic Processes and their ApplicationsVol. 195
North Carolina State University (US), University of Warwick (GB)
Peace, Justice and strong institutions
Openalex Percentile: Top 87%
Mathematical Dynamics and Fractals
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