LIPSCHITZ LABELING OF SOME TREES

Abstract A Lipschitz labeling of a graph G with vertex set V(G) with |V(G)| = m and edge set E(G) with |E(G)| = n ≥ 1 is a function f: V(G) ∪ E(G) → {1, 2, . . ., m + n} which satisfy the following conditions. (i) f is bijective. (ii) f (v) ∈ {1, 2, . . ., m} for all v ∈ V(G) (iii) f (x) ∈ {m + 1, m + 2, . . ., m + n} for all x ∈ E(G) (iv) There exists a positive integer L such that | f (x) − f (y)| ≤ L|xf − yf | for all x, y ∈ E(G) and xf = min {f (u), f (v)} for x = uv. A graph which admits a Lipschitz labeling is called a Lipschitz graph. In this work, we focus on examining the existence of Lipschitz labeling for a fork graph with two prongs, an h graph, a perfect binary tree and a flag graph.

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Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2025-11-10
DOI
https://doi.org/10.5281/zenodo.17556519
Primary Topic
Graph Labeling and Dimension Problems
Type
article
Field-Weighted Citation Impact
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article

LIPSCHITZ LABELING OF SOME TREES

Zenodo (CERN European Organization for Nuclear Research)
Graph Labeling and Dimension Problems
article

LIPSCHITZ LABELING OF SOME TREES

article en

Abstract

Abstract A Lipschitz labeling of a graph G with vertex set V(G) with |V(G)| = m and edge set E(G) with |E(G)| = n ≥ 1 is a function f: V(G) ∪ E(G) → {1, 2, . . ., m + n} which satisfy the following conditions. (i) f is bijective. (ii) f (v) ∈ {1, 2, . . ., m} for all v ∈ V(G) (iii) f (x) ∈ {m + 1, m + 2, . . ., m + n} for all x ∈ E(G) (iv) There exists a positive integer L such that | f (x) − f (y)| ≤ L|xf − yf | for all x, y ∈ E(G) and xf = min {f (u), f (v)} for x = uv. A graph which admits a Lipschitz labeling is called a Lipschitz graph. In this work, we focus on examining the existence of Lipschitz labeling for a fork graph with two prongs, an h graph, a perfect binary tree and a flag graph.

Zenodo (CERN European Organization for Nuclear Research)
Sri Venkateswara Veterinary University (IN)
Openalex Percentile: Top 40%
Graph Labeling and Dimension Problems
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