Structural and logical proof of Collatz conjecture
Finally mystery finished Every number in collatz map has different set of predecessors, and no 2 numbers share same predecessors. This argument is enough to prove collatz conjecter to be true and no cycle will ever exsist. Any cycle to exsist we must have a number that can be its own predecessor while except 1 no number can fullfil this condition. Reverse function of collatz will be like for any number n. (n.2^m -1 )/3 for any n whenever this equation wil give integer answer that number will be valid predecessor for that n. And we can have infinite many predecessors for any n. This equation could only be equal to n when n<3 for any n≥3 this equation couldn't be equal to n itself. And for n the output (valid predecessors) will be different from any other n. So when no number share same predecessors, and no number can be its own predecessor how cycles can form? This ensures every Collatz sequence will have different from each other numbers inside.
Publication Details
- Journal
- Zenodo (CERN European Organization for Nuclear Research)
- Published
- 2025-01-01
- DOI
- https://doi.org/10.5281/zenodo.16889448
- Primary Topic
- Diverse Scientific and Economic Studies
- Type
- article
- Field-Weighted Citation Impact
- 0.00