On the zeros of Riemann's Xi Function

We consider Riemann's Xi function $\xi(s)$ which is evaluated at $s = \frac{1}{2} + \sigma + i \omega$, given by $\xi(\frac{1}{2} + \sigma + i \omega)= E_{p\omega}(\omega)$, where $\sigma, \omega$ are real and compute its inverse Fourier transform given by $E_p(t)$. We study the properties of $E_p(t)$ and a promising new method is presented which could be used to show that the Fourier Transform of $E_p(t)$ given by $E_{p\omega}(\omega) = \xi(\frac{1}{2} + \sigma + i \omega)$ does not have zeros for finite and real $\omega$ when $0 < |\sigma| < \frac{1}{2}$, corresponding to the critical strip excluding the critical line.

Publication Details

Journal
Zenodo (CERN European Organization for Nuclear Research)
Published
2024-08-12
DOI
https://doi.org/10.5281/zenodo.13302059
Primary Topic
Algebraic and Geometric Analysis
Type
article
Field-Weighted Citation Impact
0.00
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article

On the zeros of Riemann's Xi Function

Zenodo (CERN European Organization for Nuclear Research)
Algebraic and Geometric Analysis
article

On the zeros of Riemann's Xi Function

article en

Abstract

We consider Riemann's Xi function $\xi(s)$ which is evaluated at $s = \frac{1}{2} + \sigma + i \omega$, given by $\xi(\frac{1}{2} + \sigma + i \omega)= E_{p\omega}(\omega)$, where $\sigma, \omega$ are real and compute its inverse Fourier transform given by $E_p(t)$. We study the properties of $E_p(t)$ and a promising new method is presented which could be used to show that the Fourier Transform of $E_p(t)$ given by $E_{p\omega}(\omega) = \xi(\frac{1}{2} + \sigma + i \omega)$ does not have zeros for finite and real $\omega$ when $0 < |\sigma| < \frac{1}{2}$, corresponding to the critical strip excluding the critical line.

Zenodo (CERN European Organization for Nuclear Research)
Openalex Percentile: Top 47%
Algebraic and Geometric Analysis
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On the zeros of Riemann's Xi Function · Zenodo (CERN European Organization for Nuclear Research) (2024) | TGRS Research Map | TGRS