On Weak Convergence of Moments of the Sum of Independently and Identically Distributed Random Variables

We study the behavior of the “moments” $\chi_n(\varepsilon) = \mathbf{E} g(|S_n|)\,\frac{\mathbf{I}[|S_n|\ge\varepsilon a_n]}{g(a_n)}$, $\varepsilon>0$, where $S_n$ is the sum of $n$ independent copies of some random variable, the sequence $\{ a_n, \, n\ge 1\}$ is monotone increasing to infinity, and the positive function $g(y)$ satisfies $g(y)\nearrow$, $g(u)/u^\gamma\searrow\,$, $y>y_0$ (with some $\gamma>0)$. In particular, the following result is proved: $\chi_n(\varepsilon) = o(1)$ (for each $\varepsilon>0$) if and only if $n\,\mathbf{E} X\,\frac{\mathbf I[|X|<a_n]}{a_n}\to 0$, $n\,\mathbf{E} X^2\,\frac{\mathbf I[|X|<a_n]}{a^2_n} \to 0$, and $n\, \mathbf{E} g(|X|)\,\frac{\mathbf I[|X|\ge a_n]}{g(a_n)} = o(1)$.

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Publication Details

Journal
Theory of Probability and Its Applications
Published
2025-10-01
DOI
https://doi.org/10.1137/s0040585x97t992495
Primary Topic
Probability and Risk Models
Type
article
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article

On Weak Convergence of Moments of the Sum of Independently and Identically Distributed Random Variables

L. V. Rozovsky
Theory of Probability and Its Applications
Probability and Risk Models
article

On Weak Convergence of Moments of the Sum of Independently and Identically Distributed Random Variables

L. V. Rozovsky
article en

Abstract

We study the behavior of the “moments” $\chi_n(\varepsilon) = \mathbf{E} g(|S_n|)\,\frac{\mathbf{I}[|S_n|\ge\varepsilon a_n]}{g(a_n)}$, $\varepsilon>0$, where $S_n$ is the sum of $n$ independent copies of some random variable, the sequence $\{ a_n, \, n\ge 1\}$ is monotone increasing to infinity, and the positive function $g(y)$ satisfies $g(y)\nearrow$, $g(u)/u^\gamma\searrow\,$, $y>y_0$ (with some $\gamma>0)$. In particular, the following result is proved: $\chi_n(\varepsilon) = o(1)$ (for each $\varepsilon>0$) if and only if $n\,\mathbf{E} X\,\frac{\mathbf I[|X|<a_n]}{a_n}\to 0$, $n\,\mathbf{E} X^2\,\frac{\mathbf I[|X|<a_n]}{a^2_n} \to 0$, and $n\, \mathbf{E} g(|X|)\,\frac{\mathbf I[|X|\ge a_n]}{g(a_n)} = o(1)$.

Theory of Probability and Its ApplicationsVol. 70(3)
Openalex Percentile: Top 62%
Probability and Risk Models
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