On Filters of Implicative Negatively Partially Ordered Ternary Semigroups

In this paper, we study a special set in an implicative n.p.o.(negatively partially ordered) ternary semigroup, and prove that a filter can be represented by the union of such sets. Indeed, let $(T, [\,\,\,],\leq,[\,\,\,]^*)$ be an implicative n.p.o. ternary semigroup. For any $a, b\in T$, we define $$S(a,b):=\{c\in T \,:\, [aa[bbc]^*]^*=1\}.$$ We have the following:\begin{enumerate} \item [(1)] A non-empty subset $F$ of $T$ isa filter if and only if it satisfies the following conditions: \begin{enumerate} \item[(F3)] $1\in F$; \item[(F4)] for any $a, b,c \in T$, if $[abc]^*\in F$ and $a,b \in F$, then $c \in F$. \end{enumerate} \item [(2)] If $T$ is commutative and $F$ is a filter of $T$, then $$F=\displaystyle\bigcup_{a,b\in F} S(a,b).$$\end{enumerate}

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Publication Details

Journal
European Journal of Pure and Applied Mathematics
Published
2025-05-01
DOI
https://doi.org/10.29020/nybg.ejpam.v18i2.5859
Primary Topic
Advanced Algebra and Logic
Type
article
Field-Weighted Citation Impact
0.00

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article

On Filters of Implicative Negatively Partially Ordered Ternary Semigroups

Thawhat Changphas, Panuwat Luangchaisri, Kansada Nakwan
European Journal of Pure and Applied Mathematics
Advanced Algebra and Logic
article

On Filters of Implicative Negatively Partially Ordered Ternary Semigroups

Thawhat Changphas, Panuwat Luangchaisri, Kansada Nakwan
article en

Abstract

In this paper, we study a special set in an implicative n.p.o.(negatively partially ordered) ternary semigroup, and prove that a filter can be represented by the union of such sets. Indeed, let $(T, [\,\,\,],\leq,[\,\,\,]^*)$ be an implicative n.p.o. ternary semigroup. For any $a, b\in T$, we define $$S(a,b):=\{c\in T \,:\, [aa[bbc]^*]^*=1\}.$$ We have the following:\begin{enumerate} \item [(1)] A non-empty subset $F$ of $T$ isa filter if and only if it satisfies the following conditions: \begin{enumerate} \item[(F3)] $1\in F$; \item[(F4)] for any $a, b,c \in T$, if $[abc]^*\in F$ and $a,b \in F$, then $c \in F$. \end{enumerate} \item [(2)] If $T$ is commutative and $F$ is a filter of $T$, then $$F=\displaystyle\bigcup_{a,b\in F} S(a,b).$$\end{enumerate}

European Journal of Pure and Applied MathematicsVol. 18(2)
Khon Kaen University (TH)
Khon Kaen University
Openalex Percentile: Top 90%
Advanced Algebra and Logic
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