COMPUTABLE TYPE OF CERTAIN QUOTIENT SPACES

Abstract We examine topological pairs $(A,B)$ which have computable type, which means that the following holds: if X is a computable topological space and $f:A\rightarrow X$ is an embedding such that $f(A)$ and $f(B)$ are semicomputable sets in X , then $f(A)$ is a computable set in X . If $(A,\emptyset )$ has computable type, we say that A has computable type. In general, if a topological pair $(A,B)$ is such that the quotient space $A/B$ has computable type, then $(A,B)$ need not have computable type. We prove the following: if $A/B$ has computable type and the interior of B in A is empty, then $(A,B)$ has computable type. On the other hand, if $(A,B)$ has computable type, then $A/B$ need not have computable type even if $\mathop {\mathrm {Int}}_{A}B=\emptyset $ . Related to this, we introduce the notion of a local computable type. We show that $\mathbb {R}^{n} /K$ has local computable type if K is a compact subspace of $\mathbb {R}^{n} $ such that $\mathbb {R}^{n} \setminus K$ has finitely many connected components.

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Publication Details

Journal
Journal of Symbolic Logic
Published
2025-04-11
DOI
https://doi.org/10.1017/jsl.2025.30
Primary Topic
Computability, Logic, AI Algorithms
Type
article
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article

COMPUTABLE TYPE OF CERTAIN QUOTIENT SPACES

Zvonko Iljazović, Matea Čelar
Journal of Symbolic Logic
Computability, Logic, AI Algorithms
article

COMPUTABLE TYPE OF CERTAIN QUOTIENT SPACES

Zvonko Iljazović, Matea Čelar
article en

Abstract

Abstract We examine topological pairs $(A,B)$ which have computable type, which means that the following holds: if X is a computable topological space and $f:A\rightarrow X$ is an embedding such that $f(A)$ and $f(B)$ are semicomputable sets in X , then $f(A)$ is a computable set in X . If $(A,\emptyset )$ has computable type, we say that A has computable type. In general, if a topological pair $(A,B)$ is such that the quotient space $A/B$ has computable type, then $(A,B)$ need not have computable type. We prove the following: if $A/B$ has computable type and the interior of B in A is empty, then $(A,B)$ has computable type. On the other hand, if $(A,B)$ has computable type, then $A/B$ need not have computable type even if $\mathop {\mathrm {Int}}_{A}B=\emptyset $ . Related to this, we introduce the notion of a local computable type. We show that $\mathbb {R}^{n} /K$ has local computable type if K is a compact subspace of $\mathbb {R}^{n} $ such that $\mathbb {R}^{n} \setminus K$ has finitely many connected components.

Journal of Symbolic LogicVol. 90(4)
University of Zagreb (HR)
Reduced inequalities
Openalex Percentile: Top 92%
Computability, Logic, AI Algorithms
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COMPUTABLE TYPE OF CERTAIN QUOTIENT SPACES — Zvonko Iljazović, Matea Čelar · Journal of Symbolic Logic (2025) | TGRS Research Map | TGRS