The nonabelian product modulo sum

Abstract It is shown that if $\{H_n\}_{n \in \omega}$ is a sequence of groups without involutions, with $1 \lt |H_n| \leq 2^{\aleph_0}$ , then the topologist’s product modulo the finite words is (up to isomorphism) independent of the choice of sequence. This contrasts with the abelian setting: if $\{A_n\}_{n \in \omega}$ is a sequence of countably infinite torsion-free abelian groups, then the isomorphism class of the product modulo sum $\prod_{n \in \omega} A_n/\bigoplus_{n \in \omega} A_n$ is dependent on the sequence.

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Publication Details

Journal
Proceedings of the Edinburgh Mathematical Society
Published
2025-04-11
DOI
https://doi.org/10.1017/s0013091525000033
Primary Topic
Advanced Topology and Set Theory
Type
article
Field-Weighted Citation Impact
0.00
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article

The nonabelian product modulo sum

Samuel M. Corson
Proceedings of the Edinburgh Mathematical Society
Advanced Topology and Set Theory
article

The nonabelian product modulo sum

Samuel M. Corson
article en

Abstract

Abstract It is shown that if $\{H_n\}_{n \in \omega}$ is a sequence of groups without involutions, with $1 \lt |H_n| \leq 2^{\aleph_0}$ , then the topologist’s product modulo the finite words is (up to isomorphism) independent of the choice of sequence. This contrasts with the abelian setting: if $\{A_n\}_{n \in \omega}$ is a sequence of countably infinite torsion-free abelian groups, then the isomorphism class of the product modulo sum $\prod_{n \in \omega} A_n/\bigoplus_{n \in \omega} A_n$ is dependent on the sequence.

Proceedings of the Edinburgh Mathematical SocietyVol. 68(4)
Universidad Politécnica de Madrid (ES)
Openalex Percentile: Top 88%
Advanced Topology and Set Theory
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