Freiman-Lev 猜想

设 $~k\geqslant 3$ 且 $~A=\{0=a_{0}<a_{1}<\cdots<a_{k-1}\}$, 其中 $~\gcd(A)=1$. Freiman-Lev 猜想 [V.F. Lev, Restricted set addition in groups, I. The classical setting, J. London Math. Soc. 62(2000), 27-40]是有关限制和集的重要猜想. 迄今为止, 当 $~a_{k-1}\geqslant 2k-2$ 时, Freiman-Lev 猜想仍未解决. 在本文中, 我们证明了当 $~a_{k-1}\geqslant 2k-2$ 且 $~a_{k-2}<2k-4$ 时, Freiman-Lev 猜想是成立的. 即, 此猜想在$~a_{k-1}\geqslant 2k-2$ 且 $~a_{k-2}\geq 2k-4$情况下仍是公开的.

Authors

Publication Details

Journal
Scientia Sinica Mathematica
Published
2025-04-08
DOI
https://doi.org/10.1360/ssm-2024-0249
Citations
1
Primary Topic
Limits and Structures in Graph Theory
Type
article
Field-Weighted Citation Impact
5.33
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article

Freiman-Lev 猜想

Yujie Wang, Min Tang
1 citations
Scientia Sinica Mathematica
Limits and Structures in Graph Theory
5.33
article

Freiman-Lev 猜想

Yujie Wang, Min Tang
article en
1 citations

Abstract

设 $~k\geqslant 3$ 且 $~A=\{0=a_{0}<a_{1}<\cdots<a_{k-1}\}$, 其中 $~\gcd(A)=1$. Freiman-Lev 猜想 [V.F. Lev, Restricted set addition in groups, I. The classical setting, J. London Math. Soc. 62(2000), 27-40]是有关限制和集的重要猜想. 迄今为止, 当 $~a_{k-1}\geqslant 2k-2$ 时, Freiman-Lev 猜想仍未解决. 在本文中, 我们证明了当 $~a_{k-1}\geqslant 2k-2$ 且 $~a_{k-2}<2k-4$ 时, Freiman-Lev 猜想是成立的. 即, 此猜想在$~a_{k-1}\geqslant 2k-2$ 且 $~a_{k-2}\geq 2k-4$情况下仍是公开的.

Scientia Sinica Mathematica
Openalex Percentile: Top 9%
Limits and Structures in Graph Theory
5.33
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Freiman-Lev 猜想 — Yujie Wang, Min Tang · Scientia Sinica Mathematica (2025) | TGRS Research Map | TGRS