On the explicit Galois group of $\mathbb{Q}\Big(a_{1}^{\frac{1}{m}}, a_{2}^{\frac{1}{m}}, \dots, a_{n}^{\frac{1}{m}}, \zeta_{m}\Big)$ over $\mathbb{Q}$

Let $m>1$ be an integer, and $\zeta_m$ denote a primitive $m$-th root of unity. For any finite set $S=\{a_{1},a_{2},\dots,a_{n}\}$ and arbitrary choice of $m$-th roots of unity $\zeta_m^{r_i}$, $0\leq r_i < m$ for $i=1,\dots,n$, we study the density of primes $\mathbf{p}$ of $\mathbb{Q}(\zeta_m)$ such that the $m$-th power residue symbol $\left(\frac{a_i}{\mathbf{p}}\right)_m=\zeta_m^{r_i}$. We calculate the explicit structure of the Galois group $\operatorname{Gal}{\mathbb{Q}(a_1^{\frac{1}{m}},\ldots,a_n^{\frac{1}{m}},\zeta_m)/\mathbb{Q}(\zeta_{m})}$ in terms of its action on $a_{i}^{\frac{1}{m}}$ for $1\leq i\leq n$.

Authors

Publication Details

Journal
Publicationes Mathematicae Debrecen
Published
2025-04-01
DOI
https://doi.org/10.5486/pmd.2025.9771
Primary Topic
Algebraic Geometry and Number Theory
Type
article
Field-Weighted Citation Impact
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article

On the explicit Galois group of $\mathbb{Q}\Big(a_{1}^{\frac{1}{m}}, a_{2}^{\frac{1}{m}}, \dots, a_{n}^{\frac{1}{m}}, \zeta_{m}\Big)$ over $\mathbb{Q}$

Prem Prakash Pandey, Mahesh Kumar Ram, C. G. Karthick Babu
Publicationes Mathematicae Debrecen
Algebraic Geometry and Number Theory
article

On the explicit Galois group of $\mathbb{Q}\Big(a_{1}^{\frac{1}{m}}, a_{2}^{\frac{1}{m}}, \dots, a_{n}^{\frac{1}{m}}, \zeta_{m}\Big)$ over $\mathbb{Q}$

Prem Prakash Pandey, Mahesh Kumar Ram, C. G. Karthick Babu
article en

Abstract

Let $m>1$ be an integer, and $\zeta_m$ denote a primitive $m$-th root of unity. For any finite set $S=\{a_{1},a_{2},\dots,a_{n}\}$ and arbitrary choice of $m$-th roots of unity $\zeta_m^{r_i}$, $0\leq r_i < m$ for $i=1,\dots,n$, we study the density of primes $\mathbf{p}$ of $\mathbb{Q}(\zeta_m)$ such that the $m$-th power residue symbol $\left(\frac{a_i}{\mathbf{p}}\right)_m=\zeta_m^{r_i}$. We calculate the explicit structure of the Galois group $\operatorname{Gal}{\mathbb{Q}(a_1^{\frac{1}{m}},\ldots,a_n^{\frac{1}{m}},\zeta_m)/\mathbb{Q}(\zeta_{m})}$ in terms of its action on $a_{i}^{\frac{1}{m}}$ for $1\leq i\leq n$.

Publicationes Mathematicae DebrecenVol. 106(3-4)
Openalex Percentile: Top 89%
Algebraic Geometry and Number Theory
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