A new trigonometric identity with applications

In this paper we obtain a new curious identity involving trigonometric functions. Namely, for any positive odd integer $n$, we prove that $$\sum_{k=1}^n(-1)^k(\cot kx)\sin k(n-k)x=\frac{1-n}2,$$ which is equivalent to the identity $$\sum_{k=1}^n(-1)^kU_{n-k}(\cos kx)=-\frac{n+1}{2},$$ where $U_m(z)$ stands for the $m$th Chebyshev polynomial of the second kind. As a consequence, for any positive odd integer $n$ and positive integer $m$, we obtain the identity $$\sum_{k=1}^n(-1)^kk^{2m}B_{2m+1}\left(\frac{n-k}2\right)=0,$$ where $B_j(x)$ denotes the Bernoulli polynomial of degree $j$.

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Publication Details

Journal
Contributions to Discrete Mathematics
Published
2024-09-23
DOI
https://doi.org/10.55016/ojs/cdm.v19i3.75984
Primary Topic
Scientific Research and Discoveries
Type
article
Field-Weighted Citation Impact
0.00

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article

A new trigonometric identity with applications

Hao Pan, Zhi-Wei Sun
Contributions to Discrete Mathematics
Scientific Research and Discoveries
article

A new trigonometric identity with applications

Hao Pan, Zhi-Wei Sun
article en

Abstract

In this paper we obtain a new curious identity involving trigonometric functions. Namely, for any positive odd integer $n$, we prove that $$\sum_{k=1}^n(-1)^k(\cot kx)\sin k(n-k)x=\frac{1-n}2,$$ which is equivalent to the identity $$\sum_{k=1}^n(-1)^kU_{n-k}(\cos kx)=-\frac{n+1}{2},$$ where $U_m(z)$ stands for the $m$th Chebyshev polynomial of the second kind. As a consequence, for any positive odd integer $n$ and positive integer $m$, we obtain the identity $$\sum_{k=1}^n(-1)^kk^{2m}B_{2m+1}\left(\frac{n-k}2\right)=0,$$ where $B_j(x)$ denotes the Bernoulli polynomial of degree $j$.

Contributions to Discrete MathematicsVol. 19(3)
Nanjing University (CN)
National Natural Science Foundation of China
Openalex Percentile: Top 82%
Scientific Research and Discoveries
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