Supercongruences involving Motzkin numbers and central trinomial coefficients

Abstract Let M n and T n denote the n th Motzkin number and the n th central trinomial coefficient respectively. We prove that for any prime $p\ge 5$ , \begin{equation*} \begin{aligned}\\[-22pt] &\sum_{k=0}^{p-1}M_k^2\equiv \left(\frac{p}{3}\right)\left(2-6p\right)\pmod{p^2},\\ &\sum_{k=0}^{p-1}kM_k^2\equiv \left(\frac{p}{3}\right)\left(9p-1\right)\pmod{p^2},\\ &\sum_{k=0}^{p-1}T_kM_k\equiv \frac{4}{3}\left(\frac{p}{3}\right)+\frac{p}{6}\left(1-9\left(\frac{p}{3}\right)\right)\pmod{p^2},\\[-6pt] \end{aligned} \end{equation*} where $\left(-\right)$ is the Legendre symbol. These results confirm three supercongruences conjectured by Z.-W. Sun in 2010.

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Publication Details

Journal
Proceedings of the Edinburgh Mathematical Society
Published
2024-10-03
DOI
https://doi.org/10.1017/s0013091524000610
Primary Topic
Advanced Mathematical Identities
Type
article
Field-Weighted Citation Impact
0.00

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article

Supercongruences involving Motzkin numbers and central trinomial coefficients

Ji-Cai Liu
Proceedings of the Edinburgh Mathematical Society
Advanced Mathematical Identities
article

Supercongruences involving Motzkin numbers and central trinomial coefficients

Ji-Cai Liu
article en

Abstract

Abstract Let M n and T n denote the n th Motzkin number and the n th central trinomial coefficient respectively. We prove that for any prime $p\ge 5$ , \begin{equation*} \begin{aligned}\\[-22pt] &\sum_{k=0}^{p-1}M_k^2\equiv \left(\frac{p}{3}\right)\left(2-6p\right)\pmod{p^2},\\ &\sum_{k=0}^{p-1}kM_k^2\equiv \left(\frac{p}{3}\right)\left(9p-1\right)\pmod{p^2},\\ &\sum_{k=0}^{p-1}T_kM_k\equiv \frac{4}{3}\left(\frac{p}{3}\right)+\frac{p}{6}\left(1-9\left(\frac{p}{3}\right)\right)\pmod{p^2},\\[-6pt] \end{aligned} \end{equation*} where $\left(-\right)$ is the Legendre symbol. These results confirm three supercongruences conjectured by Z.-W. Sun in 2010.

Proceedings of the Edinburgh Mathematical SocietyVol. 67(4)
Wenzhou University (CN)
National Natural Science Foundation of China
Openalex Percentile: Top 69%
Advanced Mathematical Identities
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